If it's not what You are looking for type in the equation solver your own equation and let us solve it.
12x^2+5x-42=0
a = 12; b = 5; c = -42;
Δ = b2-4ac
Δ = 52-4·12·(-42)
Δ = 2041
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{2041}}{2*12}=\frac{-5-\sqrt{2041}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{2041}}{2*12}=\frac{-5+\sqrt{2041}}{24} $
| x18=4.5 | | 17-+2c=24 | | 6x+20+x+40+4x-5=180 | | 10.5=(2+5)×h÷2 | | x15=2030 | | 2a-3a=-4= | | 19-g=7;g=15 | | 3x^2+60=180 | | 2,685=115m+500 | | 19-g=7;15 | | 30p+25=20p+65 | | D=144t-16t^2 | | (4x)+(2x+20)=180 | | 3x^2+60+2x^2-25=180 | | x•x+4x=5 | | 500m+115=2,685 | | x-7=3-2 | | 25p+30=65p-20 | | t=5(9+t)÷2 | | 500+115m=2,685 | | 17=(17x/3) | | x*4=180 | | (3x^2+6)=(2x^2-25) | | 25+q=1/2q=3 | | x/2=2.5 | | W(-4+z)=z+17 | | 2x*4=180 | | 17-(2c)=24 | | 9c=-99= | | 2h+11=17 | | 2+0y=5 | | 16x^2+36x^2-24x=0 |